Question 995825
Determine the value of k so that 3x-2 is a factor of 6x^3 + 5x^2 + kx + 10. 
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3x-2 is a factor if x = 2/3 is a zero.
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Solve for "k"::
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6(2/3)^3 + 5(2/3)^2 + (2/3)k + 10 = 0
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6(8/27) + 5(4/9) + (2/3)k + 10 = 0
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Multiply thru by 27 to get:
48 + 60 + 36k + 270 = 0
36k = -378
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k = -10.5
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Cheers,
Stan H.
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