Question 85248
        
          let the length of the rectangle be = X
                   width of the rectangle be = Y
                         therefore  X =2Y-5
              (p)     perimeter of the rectangle = 80  
                 therefore p = 2(length+width)
                          80 = 2(X+Y)
                 2(2Y-5+y)= 80  (substituting for X in terms of Y)
                 2(3Y -5) =80
                   3Y = 80/2 +5
                   3Y = 40+5  or 3Y = 45  or Y=45/3 =15  Y=15
                    X = 2Y-5= 2.15-5 =30-5 =25           X=25