Question 995785
Let the consecutive odd integers be
{{{ n }}} and {{{ n+ 2 }}}
given:
{{{ n + 65 = 4*( n + 2 ) }}}
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{{{ n + 65 = 4n + 8 }}}
{{{ 3n = 57 }}}
{{{ n = 19 }}}
and
{{{ n + 2 = 21 }}}
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The consecutive odd integers are 19 and 21
check:
{{{ n + 65 = 4*( n + 2 ) }}}
{{{ 19 + 65 = 4*( 19 + 2 ) }}}
{{{ 84 = 4*21 }}}
{{{ 84 = 84 }}}
OK