Question 995769
I assume, the base is ten

{{{log(x)+log(y)=4}}}..........eq.1
{{{log(x)+2log(y)=3}}}........eq.2
-------------------------subtract  1 from 2

{{{log(x)+2log(y)-(log(x)+log(y))=3-4}}}

{{{log(x)+2log(y)-log(x)-log(y)=-1}}}

{{{log(y)=-1}}}

{{{y=10^-1}}}

{{{highlight(y=1/10)}}}=> means {{{log(1/10)=-1}}}


{{{log(x)+log(1/10)=4}}}..........eq.1

{{{log(x)=4-log(1/10)}}}

{{{log(x)=4-(-1)}}}

{{{log(x)=5}}}

{{{x=10^5}}}

{{{highlight(x = 100000)}}}