Question 995537
i would say false.


y^2 = x^3 is solved as follows:


take the square root of both sides to get:


y = plus or minus sqrt(x^3)


that plus or minus tell you that you have more than one value of y for each value of x.


for example:


assume that x = 4.


you have y^2 = x^3 which means that y^2 = 64 when x is 4 because 4^3 = 64.


take the square root of both sides of that equation to get y = +/- 8.


for the value of x = 4, you can get y = + 8 or - 8.


more than one value of y for a given value of x means that you do not have a function since that violates the rules of a function that state that there is one and only one value of y for each and every value of x.


there may be only one possible value of y^2, but there are more than one possible value of y.