<PRE><B>Question 995420</B>
Find the values for x where X^2 - 12 &lt; 3x + 6. 
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x^2 - 3x - 18 &lt; 0
(x-6)(x+3) &lt; 0
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If x-6 &lt; 0 and x+3 &gt; 0, -3&lt; x &lt; 6
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Cheers,
Stan H.
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