Question 995368
Find the limit:
lim_(x->3)(2^t-8)/(t-3)
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Since (2^t-8)/(t-3) is constant with respect to x, and the limit of a constant is that constant, lim_(x->3)(2^t-8)/(t-3)=  (2^t-8)/(t-3)= (2^t-8)/(t-3)
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P.S.: you are asking us to find the limit so I'm not sure what you mean by "think derivative". If you try to derivate it you get 0 for an answer:
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d/dx(lim_(x->3)(2^t-8)/(t-3))
Rewrite: lim_(x->3)(2^t-8)/(t-3)= (-8+2^t)/(-3+t):
= d/dx((-8+2^t)/(-3+t))
The derivative of (2^t-8)/(t-3) is zero, therefore your answer is 0