Question 995362
10x+y= 12
10x= y-2 Let's go back to the first equation and plug in this value for 10x
y-2+y= 12 Add 2 on both sides and ys on left
2y= 14 Divide both sides by 2
y= 7
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The problem says:
10x= y-2 And now we say that y= 7, so 10x= 7-2= 5. Now back to the first equation with these values:
10(5)+7= 57 is your number.