Question 995258
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  4s^2\ +\ 5\ =\ \frac{1}{5}b]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  4s^2\ +\ 5\ =\ \frac{14s\ +\ 3m}{5}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  20s^2\ +\ 25\ =\ 14s\ +\ 3m]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  20s^2\ -\ 14s\ +\ 25\ =\ 3m]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  m\ =\ p(s)\ =\ \frac{20}{3}s^2\ -\ \frac{14}{3}s\ +\ \frac{25}{3}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \