Question 995226
Which pair of equations represents two perpendicular lines?
-3x+2y=10 and 3y=-2x+12
7x+4y=20 and y-3=-4/7x
x=4y+4 and 4x+4y=4
2x-5y=45 and y-5/2x=-9
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Find the slope of each eqn.
The slopes of 2 perpendicular lines will be negative inverses.
-3x+2y=10
Put in slope-intercept form y = mx + b (solve for y)
y = (3/2)x + 5
m is the slope.
m1 = 3/2
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3y=-2x+12
y = (-2/3)x + 4
m2 = -2/3
m1 = -1/m2 --> perpendicular.
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Do the others the same way.