Question 85143
note: I'm going to start out with y


{{{3(y-2)^2-3(y-2)-6}}}


Let {{{x=y-2}}}


{{{3x^2-3x-6}}}

Now factor


*[invoke change_this_name4450 3, -3, -6]


Now replace x with {{{y-2}}} to get


{{{(3(y-2)-6)((y-2)+1)}}}