Question 995162
Help me find the equation of a circle passing through points (6,0) and (24,0) and is a tangent to the y-axis 
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Sketch the figure.
The perpendicular bisector of the segment joining (6,0) and (24,0)
is the line x = 6+(24-6)/2 = 15
So the center is at (15,k).
Therefore the radius = 15, since the circle is tangent to the y-axis.
Then:
(x-15)^2 + (y-k)^2 = 15^2
Using (6,0) you get:
(81)+(0-k)^2 = 225
k^2 = 144
k = +12 or -12
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Ans: (x-15)^2 + (y-12)^2 = 15^2
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Cheers,
Stan H.
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