Question 995095
<font face="Times New Roman" size="+2">


*[tex \Large y] varies directly as *[tex \Large x] means *[tex \Large y\ =\ kx].


Substitute the initial values for *[tex \Large x] and *[tex \Large y] and then calculate *[tex \Large k].  Use this value of *[tex \Large k] to find *[tex \Large y] when *[tex \Large x] is any value you like.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \