Question 994952
An intercept means either the x coordinate is 0 or the y coordinate is 0 (or both).

To find the x intercepts, set x = 0 and solve.
{{{f(x)=2x^2+4x-3}}}
{{{f(x) = 2*2 + 4*0 -3}}}
{{{f(x) = -3}}} so one intercept is (0, -3)

To find the y intercepts, set y (or in this case f(x) ) = 0
{{{f(x)=2x^2+4x-3}}}
{{{0 = 2x^2+4x-3}}}
Use the quadratic equation to solve
*[invoke quadratic "x", 2, 4, -3 ]

There are two points where y=0. (-2.58,0) and (0.58 , 0)

You have three intercepts .. as you can see from the graph