Question 994953
.
According to the condition, your polynomial has the roots  -2,  -1,  0,  and  2.


Hence,  the polynomial is 


f(x) = a*(x-(-2))*(x-(-1))*(x-0)*(x-2) = a*(x+2)*x+1)*x*(x-2), 


where  a  is a coefficient,  an unknown real number.


To find  a,  use the condition  f(1) = 9. 


Simply substitute  x=1  into this equation  (into the polynomial).  You will get 


a*(1+2)*(1+1)*1*(1-2) = 9.


Simplify the left side.  You will get a*3*2*1*(-1) = -6a.


So,  the equation for  a  is


-6a = 9.


Hence,  a = {{{-9/6}}} = {{{-3/2}}}.


Now your polynomial is 


f(x) = {{{-3/2}}}*(x+2)*x+1)*x*(x-2).