Question 994803
n is any integer.
Your integers begin as 2n and 2n+2.


SUM:  {{{2n+2n+2=4n+2}}}
Difference Description: {{{3(2n+2)-2(2n)=6n+6-(4n)=4n+6}}}
FULL DESCRIPTION:  {{{highlight(4n+2=4n+6)}}}


Impossible because false statement.
The description needs to be better.


Maybe the difference description part should be  {{{2*2n-3(2n+2)=4n-6n-6=-2n-6}}}.
The equation for the full description would be  {{{highlight_green(4n+2=-2n-6)}}};
Maybe this would be workable.
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{{{4n+2n+2=-6}}}
{{{6n+2=-6}}}
{{{6n=-6-2}}}
{{{6n=-8}}}
{{{highlight_green(n=-4/3)}}}
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This still will not work, because your 2n and 2n+2 are NOT INTEGERS.


NO SOLUTION