Question 994795
let h be the hypotenuse
h^2 = x^2 + x^2
h^2 = 2x^2
h = x * square root(2)
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x + x + (x*square root(2) =  4+2square root(2)
x * (2 + square root(2)) = 4 + 2square root(2)
x = (4 + 2square root(2)) / (2 + square root(2))
x = 2(2 + square root(2)) / (2 + square root(2))
x = 2
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answer is A) 2