Question 994013
I almost agree with stanbon, but {{{dh/ds}}} is the ratio of increase in horizontal distance to increase in string length.
In other words, the kite travels horizontally {{{5/3}}}{{{ft}}} per {{{ft}}} of string released.
Since string is being released at {{{2}}}{{{ft/s}}} ,
the horizontal speed of the kite (in ft/s) when 125 feet of string are let out is
{{{2*(5/3)=10/3=about 3.33}}}