Question 994245

if the {{{4}}} goes over the {{{6}}} and the {{{2}}} goes over the {{{3}}} in fraction form, we have

{{{4/6+2/3-1}}}...simplify {{{4/6}}}, divide both numerator and denominator by {{{2}}}

{{{cross(4)2/cross(6)3+2/3-1}}}....write {{{1}}} as {{{3/3}}}

{{{2/3+2/3-3/3}}}

{{{(2+2-3)/3}}}

{{{(4-3)/3}}}

{{{1/3}}}