Question 994217


if a square has an area of {{{A=32cm^2}}}, then {{{a^2=32cm^2}}}=>{{{a=sqrt(32cm^2)}}}=>{{{a=sqrt(2*16cm^2)}}}=>{{{a=4sqrt(2)cm}}}


The diameter of the circle equals to {{{a =4sqrt(2)cm}}}

so the radius is {{{a =4sqrt(2)cm/2}}}=>{{{a =2sqrt(2)cm}}}

then, the area  of the  largest circle that can fit in it is:

{{{A[c]= (pi)(2sqrt(2)cm)^2 = 3.14*(4*2cm^2)=25.12cm^2}}}