Question 994177
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If one angle of a parallelogram measures *[tex \Large x], then one of the other angles measures *[tex \Large x] as well, and the other two are the supplements of *[tex \Large x].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \