Question 85113
find the domain and range of y=square root of 3+x. how do i find the domain and range?
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To find the domain you have to look for Real Number Values that x CANNOT take.
In your problem you have y=sqrt(3+x)
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That 3+x cannot be negative;it must be >=0
So solve 3+x>=0
x>-3
The domain is all Real Numbers >=3
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For the range you need to determine the Real Number values y CAN take.
Since you have y=sqrt(3+x), y must be >=0
The range is All Real Numbers >=0
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Cheers,
Stan H.