<PRE><B>Question 994077</B>
 A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of $4.90. If the number of dimes is one less than twice the number of nickels, how many of each type of coins does she have? 
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Quantity:: n + d + q = 25 coins
Value:::  5n + 10d+ 25q = 490 cents
Quantity:: d = 2n-1
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Rearrange and modify::
n +  d +  q = 25
n + 2d + 5q = 98
2n - d + 0q = 1
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Use some method to solve for n, d, and q
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I get:
n = 3 
d = 5
q = 17
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Cheers,
Stan H.
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