<PRE><B>Question 993978</B>
A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account
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Equation:
int + int = 92 dollars
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0.02x + 0.04(x+800) = 92
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2x + 4x + 3200 = 9200
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6x = 6000
x = 1000 (amt. invested at 2%)
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x+800 = 1800 (amt. invested at 4%)
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Cheers,
Stan H.
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