Question 993894


{{{x^2 + 36 < 12x }}}

{{{x^2-12x + 36 < 0 }}}

{{{x^2-12x + 6^2 < 0 }}}

{{{(x-6)^2 < 0 }}}

in this case NO solution exist; whatever you choose for {{{x}}} the result inside parentheses will be squared, so final result will ALWAYS be positive number, and NEVER negative