Question 993894
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Solve the inequality. Express your answer in interval form. 
x2 + 36 < 12x
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Inequality &nbsp;{{{x^2 + 36}}} < {{{12x}}} &nbsp;is equivalent to this one:


{{{x^2 -12 x + 36}}} < {{{0}}}.


The left side is &nbsp;{{{(x - 6)^2}}}.


It is the square of a real number, &nbsp;so it is always non-negative.


Your inequality has no solutions.

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{{{graph( 330, 330, -6.5, 10.5, -6.5, 10.5,
          x^2 -12x + 36
)}}}


The plot of &nbsp;{{{x^2 -12 x + 36}}} 

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