Question 993866
If m-p=3 and mp=-1 the what is the value of (m+p)^2? 
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m-p = 3 --> m = p+3
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m*p = -1
(p+3)*p = -1
{{{p^2 + 3p + 1 = 0}}}
*[invoke solve_quadratic_equation 1,3,1]
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p = -0.381966011250105
m = 2.618034
--> (m+p)^2 = 5
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p = -2.61803398874989
Same.