Question 993829
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{{{(x^2-8x+15)/(3x)}}} . {{{(8x)/(x-3)}}} =       (factor  {{{x^2-8x +15}}} = (x-3)*(x-5)  and then substitute it into the first ratio)       ----->


= {{{((x-3)*(x-5))/(3x)}}} . {{{(8x)/(x-3)}}} =       (cancel common factors in the numerator and denominator)       -----> 


= {{{(8/3)*(x-5)}}}.