Question 993825
this problem uses the binomial probability(P) formula
P(k successes in n trials) = (combination of n trials with k successes) * p^k * q^(n-k)
for this problem n = 10, k = (2, 3, 4, 5, 6, 7, 8, 9, 10), p = 0.25, q = 0.75
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then P(at least 2 employees say they are loyal) = P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9) + P(10) = 0.7559747695922852 approx 0.7560