Question 993828
Done, now shown fully in the previous question.


If you have any slope intercept line equation {{{y=(v/h)x+b}}}, in which the slope is {{{v/h}}}, converting into standard form is a matter of very simple algebra.


{{{y=(v/h)x+b}}}
{{{y*h=vx+bh}}}
{{{hy=vx+bh}}}
{{{hy-vx=bh}}}
{{{highlight_green(-vx+hy=bh)}}}


This result matches the form  {{{Ax+By=C}}}.  Carefully note how the coefficients A and B are used in forming the slope.  Slope is{{{-A/B}}}.