Question 993813
note that square root(a^4b^5c) times square root(a^4b^5c) = (a^4b^5c)
also square root(a^4b^5c) = a^2b^2square root(bc)
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now we multiply numerator and denominator by square root(a^4b^5c)
(a^5 bc^3) / square root(a^4b^5c) * square root(a^4b^5c) / square root(a^4b^5c) =
( (a^5 bc^3) * a^2b^2square root(bc) ) / (a^4b^5c) =
( (a^7b^3c^3square root(bc) ) / (a^4b^5c) =
( (a^3c^2square root(bc) / b^2 )