Question 993758

let numbers be {{{x}}} and {{{y}}}, and let {{{x}}} be larger number

if the sum of {{{2}}} numbers is {{{110}}}, we have

{{{x+y=110}}}

{{{y=110-x}}}.........eq.1

if the larger number {{{x}}} is {{{2}}} less than {{{7}}} times the smaller number {{{y}}} we have

{{{x+2=7y}}}

{{{y=(x+2)/7}}}......eq.2

to find the larger number {{{x}}} equal the right sides of eq.1 and eq.2:

{{{110-x=(x+2)/7}}}.........solve for {{{x}}}

{{{7(110-x)=(x+2)}}}

{{{770-7x=x+2}}}

{{{770-2=x+7x}}}

{{{768=8x}}}

{{{768/8=x}}}

{{{highlight(x=96)}}}=> larger number

and smaller number is:

{{{y=110-96}}}

{{{y=14}}}