Question 993553
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Be careful how your write your mathematical expressions.  X and x are NOT, under any circumstances the same thing, although I'm going to assume that you meant them to be.


Since *[tex \Large x^2] is always positive or zero, regardless of the value of *[tex \Large x].  So 0 is an element of the solution set.  If *[tex \Large x \not = 0], then your numerator is always positive.  Hence, for the LHS of your inequality to be positive, the denominator of your fraction must be positive.  Find the interval that contains values of *[tex \Large x] that make the denominator positive.  Since *[tex \Large x\ =\ 0] is not in this interval, the solution set is the union of the interval described and the set containing the single element 0.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \