Question 993570
Assume x is a whole number.
{{{x+(x+1)+(x+2)+(x+3)+(x+4)=63}}}


{{{5x+10=63}}}


{{{5x=53}}}


{{{x=53/5}}}, then the assumption is wrong, but we still have a result for x.
{{{highlight(x=10&3/5)}}}