Question 993532
.
How do you solve  4x+5y=25  and  8x-5y=35 when using substitution.
----------------------------------------------------------------


{{{system(4x+5y=25,
8x-5y=35)}}}.


You can express  4x  from the first equation,  4x = 25-5y,  and then substitute it into the second equation.  You will get


2*(25-5y) - 5y = 35.


Simplify and solve:


50 - 10y - 5y = 35,

15y = 30 - 35,

15y = 15, 

y = 1.


Now substitute the found value of  y=1  into the first equation to find  x.  You will get 


4x + 5*1 = 25,

4x = 20, 

x = 5.


<U>Answer</U>. &nbsp;x = 5, y = 1.