Question 993516
Slope of the line 2y+5x=0 is 
2y=-5x
y=-5x/2.  
The line perpendicular to that has a slope of 2/5, the negative reciprocal of the above slope.
now use point slope formula
y-y1=(2/5)(x-x1)
y-3=(2/5)(x+10) (watch sign here)
y-3=2x/5+4
y=(2/5)x+7
{{{graph(300,300,-10,10,-10,10,(-5x/2),(2x/5)+7)}}}