<PRE><B>Question 993511</B>
 Find the third of four consecutive odd integers given that the sum of the first two integers is four times the larger.
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1st:: 2x-3
2nd:: 2x-1
3rd:: 2x+1
4th:: 2x+3

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Equation:
(2x-3)+(2x-1) = 4(2x+3)
4x-4 = 8x+12
4x = -16
x = -4
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3rd = 2x+1 = -7
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Cheers,
Stan H.
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