Question 993500
Suppose {{{f(x)=3x–4}}} and {{{g(x)=abs(x)+3}}}.

1) 
{{{f(1/3) + g(-2)=cross(3)(1/cross(3))–4+abs(-2)+3=1-4+2+3=2}}}...(recall {{{abs(-2)=2}}} as {{{abs(2)=2}}} as well)

2) 

{{{f(1)/g(1)=(3x-4)/(abs(x)+3)=(3*1-4)/(abs(1)+3)=(3-4)/(1+3)=1/4}}}