Question 993433
Please help me solve this. I have been struggling for hours! 
1/x+1/(x-1)=2/(x^2-2x)
<pre>{{{1/x + 1/(x - 1) = 2/(x^2 - 2x)}}}, with: {{{system(x <> 0,x <> 1,x <> 2)}}}
{{{1/x + 1/(x - 1) = 2/x(x - 2)}}} ------- Factoring out right-side denominator
(x - 1)(x - 2) + x(x - 2) = 2(x - 1) ------- Multiplying by LCD, x(x - 1)(x - 2)
{{{x^2 - 3x + 2 + x^2 - 2x = 2x - 2}}} 
{{{x^2 + x^2 - 3x - 2x - 2x + 2 + 2 = 0)}}} 
{{{2x^2 - 7x + 4 = 0}}} 

As this trinomial CANNOT be factored, use the quadratic equation formula, or "completing the square" method to solve for x
You should get: {{{highlight_green(system(x = 1.780776,x = 0.7192))}}}

It would've been nice if you'd shown your "struggles!"