Question 993437
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\left(1\ +\ \frac{r}{n}\right)^{nt}]


where *[tex \Large A] is the future value, *[tex \Large P] is the present value or invested principal, *[tex \Large r] is the decimal representation of the annualized interest rate, *[tex \Large n] is the number of compounding periods per year, and *[tex \Large t] is the number of years.


So solve the following for *[tex \Large r] then calculate *[tex \Large 100r]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5865.22\ =\ 5000\left(1\ +\ \frac{r}{4}\right)^{4*8}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \