Question 993388
Replace the t in the function with the value in parentheses:
Since you did not use parentheses to clarify the function,
I will let the formula function on the site interpret.
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{{{q(t) = 6t^2 + 7 / t^2}}}
For q(2):
{{{q(2)=6(2^2)+7/2^2}}}={{{(6)(4)+7/4}}}={{{24+7/4}}}=25.75
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For q(0):
Division by zero in the (7/t^2) term makes this undefined.
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For q(-x):
{{{q(-x) = 6(-x)^2 + 7 / (-x)^2}}}={{{6x^2+7/x^2}}}