Question 993260
a rectangle is 4 feet longer than its width. if the area of the rectangle is 369 sq feet what is its width in feet?
let x=width of rectangle
x+4=length of rectangle
length*width=area
x(x+4)=369
x^2+4x-369=0
solve for x by quadratic formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
a=1, b=4, c=-369
ans: x=17.31
width=17.31 ft
length=21.31 ft