Question 993233

Three times the sum of the first and third of three consecutive odd integers is 55 more than the second integer. Find the integers
<pre>Let the 1<sup>st</sup> integer be F
Then others are: F + 2, and F + 4
According to the clues: 3(F + F + 4) = F + 2 + 55
3(2F + 4) = F + 57
Continue on to the solution for F, the first
Then add 2 to the first to get the second
Add 2 to the second or 4 to the first to determine vale of the third