Question 85000
f(x) = 2x^2 - 3x + 4 [substitute each number for x and solve the equation:
f(4)= 2(4)^2 - 3(4) + 4 
f(4)= 32-12+4
f(4)=20+4
f(4)=24
. 

f(-3)= 2(-3)^2 - 3(-3) + 4 
 f(-3)= 2(9) +9 + 4
f(-3)= 18 + 9 + 4
f(-3)= 27+4
f(-3)= 31
.
f(0) = 2(0)^2 - 3(0) + 4 
f(0) = 0- 0 + 4 
f(0)=4