Question 993233
Three times the sum of the first and third of three consecutive odd integers is 55 more than the second integer. Find the integers
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1st:: 2x-1
2nd:: 2x+1
3rd:: 2x+3
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Equation:
3[2x-1+2x+3] = 2x+1 + 55
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Solve for "x" then find the 3 consecutive odd numbers.
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Cheers,
Stan H.