Question 993127
Can you please help me solve the following problem?
Find three consecutive even integers such
 that their sum is six less than twice the
smallest
what I have come up with is not working. 
I have the smallest number =s and the
 sum=x therefore
s+(s+2)+(s+4)=x and x-6=2s+6 
But every number I plug in does not 
equate 
What am I doing wrong?
<pre>The sum is 6 less than TWICE the smallest, so you should have:
s + s + 2 + s + 4 = 2s - 6
Based on the above, you should be able to find your error(s). Move on then and solve the above for s to get
the value of the smallest integer!