Question 993127
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Find three consecutive even integers such that their sum is six less than twice the smallest.
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Let x be the smallest of these three consecutive even integers.


Then the two others are (x+2) and (x+4).


Their sum is x + (x+2) + (x+4) = 3x + 6.


According to the condition,


3x + 6 = 2x - 6.


Hence, 


x = -12.


<U>Answer</U>. The smallest of these three consecutive even integers is -12.