<PRE><B>Question 993068</B>
The length of a rectangle exceeds its width by 2 feet. If each dimension were increased by 3 feet, the area would be increased by 51 square feet. Find the dimensions. 
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Width:: x
Length:: x+2
Original Area:: x^2+2x
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After change::
Width:: x+3
Length:: x+5
New Area:: (x+3)(x+5) = x^2 + 8x + 15
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Equation:
New area - Old area = 51 ft^2
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x^2+8x+15 - (x^2+2x) = 51
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6x + 15 = 51
6x = 36
x = 6
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Cheers,
Stan H.
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