Question 992593
{{{(3a-1)^2 + (a-2)^2 = 5^2}}}
=> {{{ 9a^2-6a+1+a^2-4a+4=25}}}
=> {{{ 10a^2-10a-20=0}}}
=> {{{a^2-a-1 =0}}}
Solve for a, and choose only negative value(a is approx -0.618), since the pt. is in 3rd quadrant.