Question 992992
.
{{{system(3x-5y=900, 
5x-9y=1300)}}}.


Multiply first equation by  5  and the second equation by  -3.  Then add. You will get


-25y + 27y = 5*900 -3*1300,


2y = 4500 - 3900 = 600.


y = 300,


x = {{{(900 + 5*300)/3}}} = {{{2400/3}}} = 800.


<U>Answer</U>. &nbsp;x = 800, &nbsp;y = 300.